Spoiler alert

This guide explain how to solve the puzzle of Draumheim.

The puzzle is the game of Mastermind.

The difference here being that you have 5 slots with 7 different colors while the original Mastermind game have 4 slots with 8 different colors.

To know where the puzzle is situated, highlight the text in this quote.

To know how to get to this coordinate, highlight the text in this quote.Puzzle is at 5768, 5016.

Now for the guide to solve this puzzle...Swim in the water above Draumheim and fall from the water ceiling into the coordinate. The puzzle is behind the houses in one of the street.

First thing first, let me explain the game.

In this rendition of Mastermind, a random combination of color is hidden in the 5 slots.

The goal is to find those 5 colors with a limited number of attempts.

Here is the disposition of the playfield.

Bigger version of the picture for the text

This picture should give you a good idea of what to do.

The only other thing is the circle of orbs on top of the puzzle (not in the picture) that indicate you the time you have left. You have PLENTY of time to complete this puzzle, so don't stress over that.

In order to find the solution, we can either bang your head on the wall using random combination or use something calledDeductive Reasoning.

This guide will explain you how to apply this deductive reasoning and make this puzzle a piece of cake for anyone with good memory or with a sheet of paper and a pencil.

Now to explain how we will solve this...

There is 5 slots that we will call #1, #2, #3, #4 and #5.

There is 7 colors (White, Green, Yellow, Orange, Red, Purple, Blue) that we will call W, G, Y, O, R, P and B.

The trick to winning this every time is to find the COLORS before finding the POSITIONS.

Because the same color can be in the solution between 1 and 5 times, you need to make sure that you know if a certain color is or isn't in the solution.

To start off, choose one color.

Let's say we choose W (Because it's the first color when you click the orb).

We have the combination: W - W - W - W - W

When pulling the lever, you will know exactly how many W there is in the solution.

Here what we get...

In this case, we have 2 W in our solution.

For the next step, we want to keep an amount of W on our play field equal to the number of times it is in our solution.

In this case we have 2 W so we want to keep W in our combination twice.

We then choose a second color to test. We will choose G (Because second color).

We have the combination: W - W - G - G - G

When pulling the lever, you will know exactly how many G there is in the solution and depending on what you get, you can have more information on W positioning.

Here what we get...

So, in this case, we know that there is 0 G in our solution because only 2 lights are lit telling us that we have 2 good colors. Those colors being the 2 W from before.

We also can find out that there can be a W at #1 or #2 because one of them is at the GOOD position and the other is at the WRONG position.

It is important that you analyze the results after every pull, this allow you to gather information for the positioning for when you managed to find all the colors.

Now that we know we have 1 W at the GOOD position and 1 W at the WRONG position, we want to test a new color. The next one is Y.

So we will use this combination: W - Y - W - Y - Y

As you can see, we moved the W from #2 to #3. Because we are trying to get information about the positioning of the W at the same time as we find the new colors.

When we pull this is the result we received:

Alright, this give us more information.

For the colors we now know we have 1 Y and 2 W because 3 lights are lit.

We also know that the combination could be...

W - ? - Y - W - ?

W - ? - Y - ? - W

Y - W - W - ? - ?

Y - W - ? - W - ?

Y - W - ? - ? - W

? - W - ? - Y - W

? - W - ? - W - Y

How did I find that? From deduction. If the W on #1 is at the GOOD position, than the Y MUST be at #3 and the second W CANNOT be at #2.

If the W at #1 is NOT at the GOOD position, than W cannot be on #1 and MUST be at #2 while Y cannot be at #3.

Giving us 7 different results.

Instead of pondering on where they should be, let's just keep going and go to the next color in the list, O.

We then choose one of the combination we deduce and replace the ? by O.

In this case, I chose W - O - Y - W - O

After pulling the lever we find out that there is no O in our solution. Which also give us more information on the positioning of W and Y.

We now know that W isn't at #1 or #4 and Y isn't at #3. Then we extrapolate to deduce new combinations using what we found out before and now.

Here are the combinations we can deduce:

Y - W - W - ? - ?

? - W - ? - Y - W

Using one of those combination, we change the ? to a new color we didn't try before.

R being the next in line.

Pulling the lever give us...

With this new information, we now know that the combination is

Y - W - W - ? - ?

We also know that ? can only be P or B as they are our last 2 colors to try.

By changing ? to P we get:

We learn we have 1 P in either #4 and #5.

Which narrow our solution to either

Y - W - W - P - B

or

Y - W - W - B - P

Et voilą! We found our solution usingDeductive Reasoning.

The only thing left to do...

#Profit

Good luck and have fun!

NOTE

Because the solution is randomized every time, you can get an easier or harder time. I highly suggest to use a sheet of paper or notepad to write down the possible combination using deduction.

WARNING!

This guide doesn't give you the "solution" to solving it. The solution is RANDOM. This guide show you how to apply the strategy to find your solution.

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